Calculations and software for plumbing engineering VALTEC

VALTEC.PRG.3.1.3. Program for thermal and hydraulic calculations

The VALTEC.PRG program is publicly available and makes it possible to calculate water radiator, floor and wall heating, determine the heat demand of premises, the required flow of cold and hot water, the volume of sewage, and obtain hydraulic calculations of the internal heating and water supply networks of the facility. In addition, the user has a conveniently arranged selection of reference materials at his disposal. Thanks to its clear interface, you can master the program even without having the qualifications of a design engineer. The program meets the requirements of Russian regulatory documents governing the design and installation of engineering systems (certificate of conformity).

Difference between version 3.1.3 and version 3.1.2:
• added module for calculating pipe capacity;
• amendments have been made to the module for calculating water demand according to SNiP - it is possible to continue the calculation if the probability is more than one (insufficient number of devices);
• the “Pipes” reference table has been expanded;
• The User's Guide has been updated.

Training videos:

Calculation of heat loss of a cottage. Part 1 Calculation of heat loss in a cottage. Part 2 Calculation of underfloor heating Part 1 Calculation of underfloor heating Part 2

Calculation of heating costs

A good heating system requires quite a large financial investment. The main costs are related to:

1. Heating system equipment. It includes a boiler, pump, radiators and wiring material.
2. Installation of a heating system.
3. Fuel costs. The amount of money you spend depends on the fuel you choose.
4. Maintaining equipment in working order.

When calculating costs, the specific heat of combustion must be taken into account. Calculate by dividing the heat loss per season by the calorific value of the raw material to obtain the amount of fuel used. Multiply by cost per unit.

Another calculation method is kW consumption per hour. A house with an area of ​​120 m2 consumes 12 kW of heat energy. 8640 kW comes out per month. The method is suitable for gas and electricity users

Valtec “Sputnik” software package

The Valtec “Sputnik” software package is intended for use in the housing and communal services sector (management companies, homeowners' associations) and industry. The intuitive interface makes it easy for users to quickly learn. A number of special reports for management companies (homeowners associations, resource supply organizations) and integration with accounting programs (1C) make it easy to generate payment receipts. The control center includes reports that allow you to track emergency situations, unauthorized access to resources, and requests from subscribers from your personal account.

Integration into the Housing and Public Utilities GIS has been introduced to simplify reporting in organizations.

Main features:
• Collection of readings from metering devices, event sensors, remote resource limitation
• Online emergency monitoring
• Data storage
• Generating special reports
• Integration with related software products used in the organization’s business processes (1C, video surveillance, POS, etc.)
• Open API
• Recommendations for saving resources

To familiarize yourself with the program's capabilities: Login: demo Password: demo

In the case of a comprehensive supply of metering devices and dispatch systems, a license file that allows you to fully work with the program is issued free of charge. The server is formed on the customer's side.

As an additional paid service, it is possible to use a Valtec remote cloud server.

For commissioning, commissioning of a facility or testing of dispatch system equipment, a free test license file valid for 1 month is provided.

For details on obtaining a test license, please contact the managers working in your region.

For example, a project for a one-story house of 100 m²

To clearly explain all the methods for determining the amount of thermal energy, we suggest taking as an example a one-story house with a total area of ​​100 square meters (according to external measurements), shown in the drawing. Let us list the technical characteristics of the building:

• region of construction – temperate climate zone (Minsk, Moscow);
• thickness of external fences – 38 cm, material – sand-lime brick;
• external wall insulation – foam plastic 100 mm thick, density – 25 kg/m³;
• floors – concrete on the ground, no basement;
• ceiling - reinforced concrete slabs, insulated on the cold attic side with 10 cm foam plastic;
• windows – standard metal-plastic with 2 glasses, size – 1500 x 1570 mm (h);
• the entrance door is metal 100 x 200 cm, insulated from the inside with 20 mm extruded polystyrene foam.

The cottage has half-brick (12 cm) interior partitions; the boiler room is located in a separate building. The areas of the rooms are indicated in the drawing, the height of the ceilings will be taken depending on the explained calculation method - 2.8 or 3 m.

VALTEC SET software package

VALTEC SET is a calculation and graphic program for the design of radiator and underfloor heating systems (CO module), as well as for the design of cold and hot water supply systems (H2O module) using VALTEC equipment. The program was developed by SANKOM Sp. z oo based on the latest version of the Audytor CO program – 7.2. The product allows you to design heating and water supply systems, and perform a full range of hydraulic and thermal calculations.

Get CO Basic module keys

Get H2O Basic module keys

Types of radiators

As for which heating is best for a private home, reviews from owners are quite varied, but when it comes to radiators, many prefer aluminum models. The fact is that the power of heating batteries depends on the material. They are bimetallic, cast iron and aluminum.

One section of a bimetallic radiator has a standard power of 100-180 W, cast iron - 120-160 W, and aluminum - 180-205 W.

When purchasing radiators, you need to find out exactly what material they are made of, since this is the indicator that is required for the correct calculation of power.

VALTEC CO 3.8. Heating system design software

VALTEC CO is a calculation and graphic program for designing radiator and underfloor heating systems using VALTEC equipment, developed by SANKOM Sp. z oo based on the latest version of the Audytor CO program – 3.8. The product allows you to design and regulate heating systems, and perform a full range of hydraulic and thermal calculations. The program is certified for compliance with the current construction standards of the Russian Federation and the requirements of the Voluntary Certification System of NP "ABOK" (

).

Clarifying the speed of fluid movement

Let us express from equation (20) the speed of fluid movement:

w = 4* Vc/(π* de2) = 4*1.61*10-3/(3.14*(0.033)2) = 1.883 m/s.

3.7.
Determining the mode of fluid movement
We will determine the mode of fluid movement using the Reynolds equation (formula (3)):

Re = W* de * ρcm /μcm = 1.883*0.033*864.9/5.48*10-4 = 98073.

The movement mode is developed turbulent.

3.8.
Determination of the hydraulic resistance coefficient
Let us take the average roughness value l = 0.2 mm, then the relative roughness will be ε = l/ dе = 0.2/33 = 6.06*10-3.

Let's check the condition Re ≥ 220*ε -1.125.

220*(6.06*10-3)-1.125 = 68729, i.e. less than Re = 98073. The movement area is self-similar and the coefficient of hydraulic resistance is found according to formula (14):

1/ λ0.5 = 2*lg(3.7/ε) = 2*lg(3.7/6.06*10-3) = -6.429. Whence λ = 0.0242.

3.9.
Finding local resistance coefficients
According to paragraph 3.2. and taking into account that the local resistance coefficients are as follows:

— pipe inlet ξtr = 0.5;

— normal valve ξven = 4.7;

— elbow 90 ξcol = 1.1;

— outlet from the pipe ξintr = 1;

— measuring diaphragm (at m = (de/D)2 = 0.3, then ξd = 18.2)

∑ ξms = ξtr + 3* ξven + 3* ξcol + ξd + ξintr = 0.5 + 3*4.7 + 3*1.1 + 18.2 + 1 = 37.1.

The geometric lifting height of the mixture is 14 m.

3.10.
Determination of total pressure loss in a pipeline
The sum of all lengths of pipeline sections is 31 m, P1 = P2. Then the total hydraulic resistance of the network according to formula (18):

ΔРnet = (1 + λ * I/ de + ∑ ξms)* ρ*W2 /2 + ρ*g*hgeom + (P2 – P1) = (1 + 0.0242*31/0.033 + 37.1)*864 .9*1.8832/2 + 864.9*9.81*14 = 168327.4 Pa.

From the relation ΔРnetwork = ρ*g*h we determine hnetwork = ΔРnetwork/ (ρ*g) = 168327.4/(864.9*9.81) = 19.84 m.

3.11. Construction of characteristics of a pipeline network

We will assume that the network characteristic is a regular parabola emanating from the point with coordinates Vc = 0; h at which the point with coordinates Vc = 5.78 m3/h and hnetwork = 19.84 m is known. Let’s find the coefficient of the parabola.

The general equation of a parabola is y = a*x2 + b. Substituting the values, we have 19.84 = a*5.782 + 14. Then a = 0.1748.

Let's take several values ​​of volumetric productivity and determine the pressure h of the network.

Let's summarize the data in a table.

Table - Dependence of network pressure on pump performance

Based on the obtained points, we build a network characteristic (line 1 in Figure 2).

Figure 2 – Combination of network and pump characteristics:

1 – network characteristics; 2 – pump characteristics; 3 - design point; 4 – operating point.

VALTEC H2O 1.6. Software for designing water supply systems

VALTEC H2O is a program for designing cold and hot water supply systems using VALTEC plumbing engineering products, developed by SANKOM Sp. z oo based on the calculation and graphic program Audytor H2O 1.6. Allows you to perform a complete calculation and design of a hydraulically balanced water supply system. The program meets the requirements of the Voluntary Certification System of NP “ABOK” and SNiP 2.04.01-85* “Internal water supply and sewerage of buildings” ().

Selection of standard pipeline diameter

The industry produces a standard assortment of pipes, among which it is necessary to select pipes with a diameter closest to the design one (clause 3.4.). Pipes are designated dн x δ, where dн is the outer diameter of the pipe, mm; δ – pipe wall thickness, mm. In this case, the internal diameter of the pipe din = dn – 2* δ.

The standard dimensions of pipes according to GOST 8732-78 are the following row, mm: 14x2; 18x2; 25x2; 32x2.5; 38x2.5; 45x3; 57x3; 76x3.5; 89x4.5; 108x4.5; 133x4; 159x4.5; 219x6; 272x7; 325x8; 377x10; 426x11; 465x13.

According to clause 3.4. the internal size of the pipe is 32 mm, then the external size dн = 32 + 2 * 2.5 = 37 mm. The closest pipe size is 38x2.5 mm. The standard internal diameter is 33 mm, so we take the equivalent diameter dе = 0.033 m.

Valtec “Sputnik” equipment configurator

Configurator software is a modular configurator for various metering devices and equipment. Allows commissioning of the Valtec “Sputnik” automated energy metering system.

The configurator includes the following modules:
• polling of metering devices via radio channel using radio modem VT.WRM.MASTER.0
• module for reading data from VT.WRM hubs
• module for configuring wireless pulse counter-recorder GSM/GPRS VT.WLR.GSM
• module for configuring a wireless pulse counter-recorder with a radio channel (LoRAWAN 868 MHz) VT.LR
• module for configuring pulse counter-recorder SIPU (RS485/M-Bus) VT.MB/ VT.RS

Determination of mixture characteristics

Since the problem statement does not specify a change in temperature, we assume the flow is isothermal, i.e. maintaining a temperature of 30°C throughout. The composition of a mixture of benzene and toluene allows you to determine the density and viscosity of the mixture.

Density at 30 C: benzene ρb = 868.5 kg/m3 and density of toluene ρt = 856.5 kg/m3, then the density of the mixture: ρcm = 0.7* ρb + 0.3* ρt = 0.7*868, 5 + 0.3*856.5 = 864.9 kg/m3.

Viscosity at 30 C: benzene μb = 5.6*10-4 Pa*s and toluene viscosity μt = 5.22*10-4 Pa*s, then the viscosity of the mixture: lg μcm = 0.7*lg μb + 0, 3*lg μt = 0.7*lg (5.6*10-4) + 0.3*lg (5.22*10-4) = - 3.261, and μcm = 5.48*10-4 Pa* With .

VHM-T Service. Program for working with VALTEC heat meters

The VHM-T Service program is designed to work with VALTEC VHM-T heat meters in terms of:
• reading current meter readings and characteristics;
• working with daily, monthly and annual archives;
• generation of thermal energy consumption accounting sheets;
• settings of date, time and automatic transition to summer/winter time (if necessary);
• counter settings for operation in automated data accounting systems.

Work computer software requirements

• operating system Windows XP Service Pack 3 (32/64 bit) or higher;
• Visual C++ Redistributable Packages for Visual Studio 2013 (free download available from microsoft.com). As a rule, these packages are already present in versions of Windows 7 and higher with the latest updates.

The interaction of the working computer with the heat meter is carried out through an optoelectronic sensor with the appropriate drivers installed in the system.

Setting up communication between the program and the meter

1. Connect the optoelectronic sensor to the computer.
2. On the front panel of the heat meter, press and hold the button (about 8 seconds) until the “=” symbol appears in the lower right corner of the screen.
3. Bring the optoelectronic sensor to the opto-receiver of the meter on the front panel.
4. Give a command to establish a connection in the program.

— Windows XP/Server 2003/Vista/7/8/8.1 (v6.7)

To activate the program, you must register again. The activation key is sent to the user's email address within 1-2 days.

If you have any questions about working with the program, you can ask them at:

Programs for old-style counters

Forced circulation systems

Such systems usually operate on gas or electric boilers. The diameter of the pipes for them should be chosen as small as possible, since forced circulation is provided by the pump. The feasibility of small-diameter pipes is explained by the following factors:

• a smaller cross-section (most often these are polymer or metal-plastic pipes) allows you to minimize the volume of water in the system and, therefore, speed up its heating (the inertia of the system decreases);
• installation of thin pipes is much simpler, especially if they need to be hidden in walls (making grooves in the floor or walls requires less labor);
• pipes of small diameters and connecting fittings for them are cheaper, therefore, the total cost of installing the heating system is reduced.

With all this, the size of the pipes must optimally correspond to the indicators provided for by the technological calculations. If these recommendations are not followed, the efficiency of the heating system will decrease and its noise will increase.

Adjusting results

In order to obtain a more accurate calculation, you need to take into account as many factors as possible that reduce or increase heat loss. This is what the walls are made of and how well they are insulated, how large the windows are and what kind of glazing they have, how many walls in the room face the street, etc. To do this, there are coefficients by which you need to multiply the found values ​​of heat loss in the room.

The number of radiators depends on the amount of heat loss

Window

Windows account for 15% to 35% of heat loss. The specific figure depends on the size of the window and how well it is insulated. Therefore, there are two corresponding coefficients:

• ratio of window area to floor area: 10% - 0.8
• 20% — 0,9
• 30% — 1,0
• 40% — 1,1
• 50% — 1,2

Walls and roof

To account for losses, the material of the walls, the degree of thermal insulation, and the number of walls facing the street are important. Here are the coefficients for these factors.

Thermal insulation level:

• brick walls two bricks thick are considered the norm - 1.0
• insufficient (absent) - 1.27
• good - 0.8

Presence of external walls:

• interior space - no losses, coefficient 1.0
• one - 1.1
• two - 1.2
• three - 1.3

The amount of heat loss is influenced by whether the room is located on top or not. If there is a habitable heated room on top (the second floor of a house, another apartment, etc.), the reduction factor is 0.7, if there is a heated attic - 0.9. It is generally accepted that an unheated attic does not affect the temperature in any way (coefficient 1.0).

It is necessary to take into account the characteristics of the premises and climate in order to correctly calculate the number of radiator sections

If the calculation was carried out by area, and the ceiling height is non-standard (a height of 2.7 m is taken as the standard), then a proportional increase/decrease using a coefficient is used. It is considered easy. To do this, divide the actual ceiling height in the room by the standard 2.7 m. You get the required coefficient.

Let's do the math for example: let the ceiling height be 3.0m. We get: 3.0m/2.7m=1.1. This means that the number of radiator sections that was calculated by area for a given room must be multiplied by 1.1.

All these norms and coefficients were determined for apartments. To take into account the heat loss of a house through the roof and basement/foundation, you need to increase the result by 50%, that is, the coefficient for a private house is 1.5.

Climatic factors

Adjustments can be made depending on average winter temperatures:

• -10°C and above – 0.7
• -15оС — 0.9
• -20оС — 1.1
• -25оС — 1.3
• -30оС — 1.5

Having made all the required adjustments, you will receive a more accurate number of radiators required to heat the room, taking into account the parameters of the premises.
But these are not all the criteria that influence the power of thermal radiation. There are also technical subtleties, which we will discuss below. Date: September 25, 2022

Data Consistency

To coordinate data in Project Studio CS Heating, a specialized Project Manager is used. All drawings, specifications and other project documents are guaranteed to refer specifically to the current Project Studio CS Heating project. This allows you to obtain accurate equipment specifications. In addition, the equipment specification always corresponds to the current state of the heating system model.

It is also possible to obtain floor-by-floor equipment specifications. This is especially important in cases where a large facility is being designed and it is necessary to determine what heating equipment needs to be delivered to a specific floor.

The specification template can be customized, which provides a great advantage in obtaining the documentation required by the user.

What does thermal conductivity depend on?

Heat transfer depends on factors such as:

• The material from which the structure is constructed – different materials differ in their ability to conduct heat. Thus, concrete and various types of bricks contribute to large heat loss. Galvanized logs, timber, foam and gas blocks, on the contrary, with a smaller thickness, have lower thermal conductivity, which ensures heat retention inside the room and much lower costs for insulation and heating of the building.
• Wall thickness - the greater this value, the less heat transfer occurs through its thickness.
• Humidity of the material - the higher the humidity of the raw material from which the structure is constructed, the more heat it conducts and the faster it collapses.
• The presence of air pores in the material - air-filled pores prevent accelerated heat loss. If these pores are filled with moisture, heat loss increases.
• The presence of additional insulation - walls lined with a layer of insulation on the outside or inside have heat loss values ​​that are several times less than those that are not insulated.

In construction, along with the thermal conductivity of walls, such a characteristic as thermal resistance (R) has become widespread. It is calculated taking into account the following indicators:

• thermal conductivity coefficient of wall material (λ) (W/m×0С);
• thickness of the structure (h), (m);
• presence of insulation;
• material moisture content (%).

The lower the thermal resistance value, the more the wall is susceptible to heat loss.

Thermal engineering calculations of enclosing structures for this characteristic are performed using the following formula:

R= h/ λ; (m2×0С/W)

Example of calculating thermal resistance:

Initial data:

• the load-bearing wall is made of dry pine beams 30 cm (0.3 m) thick;
• thermal conductivity coefficient is 0.09 W/m×0С;
• calculation of the result.

Thus, the thermal resistance of such a wall will be:

R=0.3/0.09=3.3 m2×0С/W

If the obtained value is equal to or greater than the standard value, then the material and thickness of the wall structures are chosen correctly. Otherwise, the building must be insulated to achieve the standard value.

If there is insulation, its thermal resistance is calculated separately and summed up with the same value of the main wall material. Also, if the material of the wall structure has high humidity, the appropriate thermal conductivity coefficient is used.

To more accurately calculate the thermal resistance of a given structure, similar values ​​for windows and doors facing the street are added to the result obtained.

Lists of drawings, documents and quantities of work

It is possible to receive in a semi-automatic mode a list of working drawings of the main set in accordance with GOST 21.101−2020, a list of reference and attached documents in accordance with GOST 21.101−2020 and a statement of the volume of construction and installation work in accordance with GOST 21.111−84. These statements can be output in Word, Excel or AutoCAD.