How to convert cubic meters to kilocalories?

How to convert Gcal?

To find out how many Gcal is obtained, you need to multiply the available number of kW by a constant value, 0.00086. Let's look at an example. Suppose you need to convert 250 kW into calories. 250 kW x 0.00086 = 0.215 Gcal/hour.

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How to calculate how many gigalories per cubic meter. meter as an example

Measures of energy and volume are different quantities. Simple calculations will help you compare them.

Example: The coolant temperature in an apartment building should be at least 55 ⁰C, the cold water temperature should be approximately 5 ⁰C.

To heat a cubic meter you will need:

(55-5)×0.001=0.05 Gcal.

Heat losses due to imperfect thermal insulation are inevitable; losses of 20% are included in the calculations . This means that actually heating will require 0.06 Gcal.

This ratio allows the heat meter to determine the consumption of heated water.

Example: in a 100-apartment residential building, the heat meter showed 150 Gcal in the summer, when only coolant for domestic needs is consumed. In 20 apartments, hot water consumption is determined by individual meters; the total consumption for these apartments was 400 m³.

The whole house consumes: 150÷0.06=2500 m³. This means that the remaining apartments account for: 2500-400 = 2100 m³. Next, 2100 m³ is divided by the actual number of residents.

This technique allows you to convert thermal energy values into volumetric coolant flow rates and vice versa.

In houses with an open heating system, the difference in water meter readings on the supply and return pipes will indicate the amount of coolant consumed for heating and, after recalculation, the heat energy consumption.

The calculations are for reference only and serve to control the consumption of heat and water supply.

Why do I pay for heating in the summer?

Heating charges can be charged either only during the heating season (as in the examples above) or all year round.
The same amounts are obtained per year, but the first method is simpler and, most importantly, it is transparent for the recipient of the receipt. The second method is quite complicated and often causes confusion among residents. In this case, all heating costs for the year are added up and divided by twelve.

The Petrovs have the same apartment as the Ivanovs, but the local administration chose the second method, payment during the calendar year. There are no meters.

Let the heating season last 7 months. Divide 7 by 12 to get approximately 0.58. Let's multiply by the number obtained in the first example: 0.58 × 1170 = 678.6 rubles. This is the amount you will have to pay for heating every month throughout the year.

It is not difficult to calculate that in a year the total amount will be the same as the Ivanovs (from the first example) for seven months of the heating season.

If there is a house or apartment meter, and the fee is calculated in the second way, everything is not so simple. It is not the latest meter readings that are taken into account, but the average monthly heat consumption for the past year (total heat for the entire heating season divided by twelve). Or, if the meter has just been installed, the same “heating standards”.

The result, naturally, never coincides with reality, and at the beginning of next year it has to be corrected. Therefore, deductions or additional payments appear on receipts - so that the amount that appears on the meter is obtained.

In Novosibirsk, by decree of the regional governor, this method was adopted.

However, it is so inconvenient (especially for residents) that many management companies unofficially allow payment “based on consumption.” That is, in the first, simple and understandable way.

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How to convert gigacalories to cubic meters

When receiving utility bills, it is quite difficult to understand many aspects of the calculations and understand: where did this or that figure come from? One of the most striking examples of such “translation difficulties” is payment for supplied heat. If your home has a single heat meter installed, then you will receive bills for the Gcal (gigacalories) used, but the tariff for hot water, as you know, is set for cubic meters. How to figure out how to calculate the cost of heat?

Instructions

Perhaps the greatest difficulty lies precisely in the technical impossibility of converting gigacalories into cubic meters or vice versa. These are completely different physical quantities: one serves to measure thermal energy, the other – volume, and, as a basic physics course suggests, they are incomparable. The task of the utility consumer ultimately comes down to calculating the ratio of the amount of heat expended and the volume of hot water consumed.

In order not to get completely confused, it is worth starting with determining the calculated values. So, by calorie we mean the amount of heat that is necessary to heat one cubic centimeter of water by 1°C. There are a billion calories in a Gcal, and a million centimeters in a cubic meter, therefore, to heat one cubic meter of water by 1°C you will need 0.001 Gcal.

Considering that hot water should not be colder than 55°C, and cold water arrives at a temperature of 5°C, it is obvious that it will need to be heated by 50°C, that is, spend 0.05 Gcal of thermal energy on each cubic meter. In the sphere of housing and communal services tariffs, there is a slightly higher heat consumption standard for heating one cubic meter of water - 0.059 Gcal, this is due to heat losses that occur when transporting water through a pipeline.

Then everything is simple, divide the heat consumption according to the readings of the house meter by the number of residents. In this way, obtain the heat consumption for each resident, and dividing the resulting figure by the standard 0.059 is the volume of hot water in cubic meters that must be paid for by each resident. The only subtlety in this calculation is the need to subtract from it those residents who have consumption meters installed in their apartment.

Let's consider the calculation using an example: the consumption according to a common house meter was 30 Gcal, residents who have internal metering devices used a total of 35 m³ of hot water, residents without metering devices in the house - 75 people.

We count:

35*0.059 = 2.065 – this is the amount of heat consumed by residents who have metering devices;

30-2.065 = 27.935 Gcal – the balance of consumption for the remaining residents;

27.935/75 = 0.372 Gcal – heat consumption per resident;

0.372/0.059 = 6.31 m³ of hot water will be billed to each tenant whose apartments are not equipped with metering devices.

More details: https://www.kakprosto.ru/kak-108400-kak-perevesti-gigakaloriyu-v-kubicheskie-metry#ixzz2mtUe7egh

How is the heat supply fee calculated?

If water supply for domestic needs is assessed using in-house metering devices or approved standards, then the payment for heat supply is calculated based on approved methods.

There are two options for accrual periods:

For the heating season.
For a calendar year.

The method for calculating heat supply costs depends on several factors:

on the type of installed hot water supply system: open or closed;
from the presence of communal and intra-apartment heat and water supply meters.

The logic of the calculations is the same: distribution of all thermal energy consumed by the house over the area of residential and non-residential heated premises, i.e. Residents pay part of the costs in proportion to the heated area occupied.

The heating fee is equal to: P = Q×S×T, where:

Q is the amount of thermal energy consumed per 1 m3 of occupied space, including general house expenses;
S - occupied area;
T is the tariff for thermal energy established by local authorities.

Tariffs are reviewed annually and approved for each heat supply system individually.

How to calculate heating by area?

Often, 100 W of thermal energy is taken as a norm per 1 m2 of area - this is considered the simplest method for those who do the calculation of heating power by volume of the room with their own hands. For calculations, use the formula Q = S×100, where: Q is the required thermal power for the room; S – room area (m²);

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How much heat does 1 kg of coal generate?

Type of fuel	Unit change	Specific heat of combustion
Coal (W=10%)	1 kg	6450
Brown coal (W=30…40%)	1 kg	3100
Coal-anthracite	1 kg	6700
Charcoal	1 kg	6510

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General information about Gcal calculations

To calculate Gcal, it is necessary to make special calculations, the procedure of which is established by special regulations. The calculation is carried out by utility services, which can explain to you the procedure for calculating Gcal, as well as decipher any unclear points.

If you have an individual device installed, you will be able to avoid any problems and overpayments. All you need to do is take the readings from the meter every month and multiply the resulting number by the tariff. The amount received must be paid for the use of heating.

When you need to dot all the i’s

But a completely reasonable question arises: “How to count something that is invisible and can disappear instantly, literally out the window.” There is no need to despair of this struggle with the air; it turns out that there are quite clear mathematical calculations of the calories received for heating.

Moreover, all these calculations are hidden in official documents of state utility organizations. As usual in these institutions, there are several such documents, but the main one is the so-called “Rules for accounting of thermal energy and coolant”. It is he who will help solve the question - how to calculate Gcal for heating.

The actual problem can be solved quite simply and no calculations will be needed if you have a meter not just for water, but for hot water. The readings of such a meter are already “filled” with data on the heat received. When taking readings, you multiply it by the cost tariff and get the result.

Find out also how to hide heating pipes - three main ways.

How many Gcal are in 1 cubic meter of gas? How to convert gas to gigacalories?

I had my own experience of doubting the quality of gas when purchasing a 50-liter gas cylinder for use in the country. I asked a similar question about how the cylinder must somehow be designed for a certain amount of heat released during combustion. To which I received a positive response and even got acquainted with the Gas Quality Certificate, which indicated certain numbers in the table, as an average value based on the data obtained during testing, and even comparative readings in GOST.

I’ll start with GOST; the calorific value is regulated by the document GOST 5542-2014, which specifies two recommended parameters for physical and chemical indicators.

1) Lower calorific value under standard conditions, MJ/m3 (cube) kcal/m3 (cube)

Limit rate above - 31.80 MJ/m3 (7600 kcal/m3)

2) Range of values of the Wobbe number (highest) under standard conditions, MJ/m3 (cube) kcal/m3 (cube)

Limit rate - From 41.20 MJ/m3 to 54.50 MJ/m3 (from 9840 kcal/m3 to 13020 kcal/m3)

Test methods, formulas and calculations are described in the document GOST 31369-2008

Let's return from the documents to your questions, but first I would like to note that, firstly, we are interested in the value of the lower calorific value, since it is this that is more or less true under standard (domestic) operating conditions.

I would also like to note that official documents express data in MJ/m3 and kcal/m3; if they are converted to Gcal/m3, then a coefficient is applied.

Let's start with the first question:

How many Gcal are in 1 cubic meter of gas?

According to GOST, this value is equal to (attention! not less than) 7600 kcal/m3

Second question:

How many Gcal are in 1 liter of gas?

Since all documents regulate a cubic meter, to determine a liter it is necessary to divide by 1000, since there are 1000 liters in 1 m3

7600/1000=7.6 kcal/m3

Third question:

How many Gcal are in 1 50 liter gas cylinder?

If 1 liter contains a minimum of 7.6 kcal/m3, then 50 liters theoretically contain 50 times more

7.6*50=380 kcal/m3

In practice, there are never 50 liters in a cylinder; at most, if there are 40-42 liters, then this is good, you need to focus on a maximum of 40 liters, which means the answer will be:

304 kcal/m3

Fourth question:

How to convert gas to gigacalories?

Let's start with the fact that a Gigacalorie is nothing more than 1,000,000,000 Calories, which reflect a certain amount of heat that must be spent to heat up the water.

1 calorie heats 1 gram of pure water at normal pressure by 1 degree Celsius.

Accordingly, 1 Gcal heats the same water by 1 degree in the amount of 1000 liters.

To convert the heat of gas into Gcal (gigacalories), you need to use a coefficient of 10 to the 9th power, i.e. by one billion.

In addition, I would like to note that all the above standards are minimum standards, the exact ones must be checked with gas sellers, these standards are specified in quality passports.